What is the derivative of 9(x^3-x)^4 ?

The derivative of 9(x^3-x)^4 is 36(x^3-x)^3(3x^2-1)

What is the first derivative of 9(x^3-x)^4 ?

The first derivative of 9(x^3-x)^4 is 36(x^3-x)^3(3x^2-1)

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derivative of

9 (x^{3} - x)^{4}

36 (x^{3} - x)^{3} (3 x^{2} - 1)

Solution steps

\frac{d}{d x} (9 (x^{3} - x)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} ((x^{3} - x)^{4})

Apply the chain rule:

4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

= 4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

\frac{d}{d x} (x^{3} - x) = 3 x^{2} - 1

= 9 \cdot 4 (x^{3} - x)^{3} (3 x^{2} - 1)

Simplify

= 36 (x^{3} - x)^{3} (3 x^{2} - 1)

\frac{\partial}{\partial x} (5 sin (2 (5 x + 6 y)))

\int x^{2} \cdot x^{3} + 1 d x

x \to 2 lim (\frac{x ^{3} - 1}{x - 1})

\frac{d}{d x} (1 + ln (x))

n \to \infty lim (r^{n})

What is the derivative of 9(x^3-x)^4 ?
The derivative of 9(x^3-x)^4 is 36(x^3-x)^3(3x^2-1)
What is the first derivative of 9(x^3-x)^4 ?
The first derivative of 9(x^3-x)^4 is 36(x^3-x)^3(3x^2-1)