What is the solution for (dy)/(dx)=(x+y-2)^2 ?

The solution for (dy)/(dx)=(x+y-2)^2 is y=tan(x+c_{1})-x+2

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(dy)/(dx)=(x+y-2)^2

\frac{d y}{d x} = (x + y - 2)^{2}

y = tan (x + c_{1}) - x + 2

Solution steps

\frac{d y}{d x} = (x + y - 2)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x + 2

y = tan (x + c_{1}) - x + 2

y = \frac{C}{x}

\int (\frac{1}{x} - \frac{2}{x ^{2}} + \frac{5}{x ^{3}}) d x

- y

x \to 0 lim (4 x - ln (4 x + 1))

x \to 0 lim (\frac{12}{x ^{2}})

What is the solution for (dy)/(dx)=(x+y-2)^2 ?
The solution for (dy)/(dx)=(x+y-2)^2 is y=tan(x+c_{1})-x+2