What is (\partial)/(\partial x)(sin(x-y^2)) ?

The answer to (\partial)/(\partial x)(sin(x-y^2)) is cos(x-y^2)

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(\partial)/(\partial x)(sin(x-y^2))

\frac{\partial}{\partial x} (sin (x - y^{2}))

cos (x - y^{2})

Solution steps

\frac{\partial}{\partial x} (sin (x - y^{2}))

Treat

y

as a constant

Apply the chain rule:

cos (x - y^{2}) \frac{\partial}{\partial x} (x - y^{2})

= cos (x - y^{2}) \frac{\partial}{\partial x} (x - y^{2})

\frac{\partial}{\partial x} (x - y^{2}) = 1

= cos (x - y^{2}) \cdot 1

Simplify

= cos (x - y^{2})

\int_{- 1}^{2} (x + 2 - x^{2})^{2} d x

t \to 1 lim (f (t))

y^{^{''}} + 16 y = 5 sec (4 t)

\int \frac{1}{( s ^{2} - 2 s + 1 ) ^{2}} d s

\int_{0}^{7} (e^{t} + e^{- t}) d t

What is (\partial)/(\partial x)(sin(x-y^2)) ?
The answer to (\partial)/(\partial x)(sin(x-y^2)) is cos(x-y^2)