What is the integral of-2ln(x^2-1) ?

The integral of-2ln(x^2-1) is -2(xln(x^2-1)+ln|x+1|-ln|x-1|-2x)+C

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integral of-2ln(x^2-1)

\int - 2 ln (x^{2} - 1) d x

- 2 (x ln (x^{2} - 1) + ln ∣ x + 1 ∣ - ln ∣ x - 1 ∣ - 2 x) + C

Solution steps

\int - 2 ln (x^{2} - 1) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int ln (x^{2} - 1) d x

Apply Integration By Parts

: x ln (x^{2} - 1) - \int \frac{2 x ^{2}}{x ^{2} - 1} d x

= - 2 (x ln (x^{2} - 1) - \int \frac{2 x ^{2}}{x ^{2} - 1} d x)

\int \frac{2 x ^{2}}{x ^{2} - 1} d x = - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + 2 x

= - 2 (x ln (x^{2} - 1) - (- ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + 2 x))

Simplify

= - 2 (x ln (x^{2} - 1) + ln ∣ x + 1 ∣ - ln ∣ x - 1 ∣ - 2 x)

Add a constant to the solution

= - 2 (x ln (x^{2} - 1) + ln ∣ x + 1 ∣ - ln ∣ x - 1 ∣ - 2 x) + C

f (x) = 11 x - 1

x \to 4 lim ((3 x - 3)^{\frac{5}{2}})

\int \frac{( 14 x ^{3} + 2 x + 1 )}{x ^{3}} d x

\frac{d}{d x} (sin (x^{2} - 2 x + 6))

y^{2} = x + 1, x = 1

What is the integral of-2ln(x^2-1) ?
The integral of-2ln(x^2-1) is -2(xln(x^2-1)+ln|x+1|-ln|x-1|-2x)+C