What is the tangent of f(x)= 4/(x^2),(1,4) ?

The tangent of f(x)= 4/(x^2),(1,4) is y=-8x+12

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tangent of f(x)= 4/(x^2),(1,4)

tangent of

f (x) = \frac{4}{x ^{2}}, (1, 4)

y = - 8 x + 12

Solution steps

Find the slope of

f (x) = \frac{4}{x ^{2}} : \frac{df ( x )}{d x} = - \frac{8}{x ^{3}}

Compute the slope of

f (x) = \frac{4}{x ^{2}}

(1, 4) : m = - 8

Find the line with slope m=

- 8

and passing through

(1, 4) : y = - 8 x + 12

y = - 8 x + 12

f (x) = (3 - e^{- 4 x})^{4}

\frac{d}{d x} (2 + 2 cos (x))

29 - 11 x, 1 - x^{2}

\frac{d ^{2} y}{d x ^{2}} + 5 \frac{d y}{d x} + 6 y = 2 e^{x}

What is the tangent of f(x)= 4/(x^2),(1,4) ?
The tangent of f(x)= 4/(x^2),(1,4) is y=-8x+12