What is the derivative of g(x)=sqrt(6-x) ?

The derivative of g(x)=sqrt(6-x) is -1/(2sqrt(6-x))

What is the first derivative of g(x)=sqrt(6-x) ?

The first derivative of g(x)=sqrt(6-x) is -1/(2sqrt(6-x))

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derivative of

g (x) = 6 - x

- \frac{1}{2 6 - x}

Solution steps

\frac{d}{d x} (6 - x)

Apply the chain rule:

\frac{1}{2 6 - x} \frac{d}{d x} (6 - x)

= \frac{1}{2 6 - x} \frac{d}{d x} (6 - x)

\frac{d}{d x} (6 - x) = - 1

= \frac{1}{2 6 - x} (- 1)

Simplify

= - \frac{1}{2 6 - x}

\frac{1}{1 - x}, 0, 1

\int 3 x^{5} d x

n = 9 \sum \infty e^{3 - 4 n}

y = cos^{4} (x) - sin^{4} (x)

\int sin^{3} (x) cos (d) x d x

What is the derivative of g(x)=sqrt(6-x) ?
The derivative of g(x)=sqrt(6-x) is -1/(2sqrt(6-x))
What is the first derivative of g(x)=sqrt(6-x) ?
The first derivative of g(x)=sqrt(6-x) is -1/(2sqrt(6-x))