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Popular >

derivative of f(x)=sqrt(8x^2-x)

Solution

derivative of

f (x) = 8 x^{2} - x

Solution

\frac{16 x - 1}{2 8 x ^{2} - x}

Solution steps

\frac{d}{d x} (8 x^{2} - x)

Apply the chain rule:

\frac{1}{2 8 x ^{2} - x} \frac{d}{d x} (8 x^{2} - x)

= \frac{1}{2 8 x ^{2} - x} \frac{d}{d x} (8 x^{2} - x)

\frac{d}{d x} (8 x^{2} - x) = 16 x - 1

= \frac{1}{2 8 x ^{2} - x} (16 x - 1)

Simplify

\frac{1}{2 8 x ^{2} - x} (16 x - 1) : \frac{16 x - 1}{2 8 x ^{2} - x}

= \frac{16 x - 1}{2 8 x ^{2} - x}

Popular Examples

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\frac{\partial}{\partial x} (ln (x^{3} + y^{7}))

derivative of sin^{-5}(x-cos^3(x))

\frac{d}{d x} (sin^{- 5} (x) - cos^{3} (x))

integral of ((x+1))/(sqrt(x))

\int \frac{( x + 1 )}{x} d x

(csc^{2} (x))^{^{'}}

Frequently Asked Questions (FAQ)

What is the derivative of f(x)=sqrt(8x^2-x) ?
The derivative of f(x)=sqrt(8x^2-x) is (16x-1)/(2sqrt(8x^2-x))
What is the first derivative of f(x)=sqrt(8x^2-x) ?
The first derivative of f(x)=sqrt(8x^2-x) is (16x-1)/(2sqrt(8x^2-x))