What is the derivative of tan(3x+1) ?

The derivative of tan(3x+1) is sec^2(3x+1)*3

What is the first derivative of tan(3x+1) ?

The first derivative of tan(3x+1) is sec^2(3x+1)*3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (tan (3 x + 1))

sec^{2} (3 x + 1) \cdot 3

Solution steps

\frac{d}{d x} (tan (3 x + 1))

Apply the chain rule:

sec^{2} (3 x + 1) \frac{d}{d x} (3 x + 1)

= sec^{2} (3 x + 1) \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= sec^{2} (3 x + 1) \cdot 3

\int 19 sin^{2} (x) cos^{2} (x) d x

y = \frac{x + 1}{2 x - 1}

y^{^{'}} - y = e^{2 x}

\int 12 cos (4 x) d x

f (x) = 5 x + 1

What is the derivative of tan(3x+1) ?
The derivative of tan(3x+1) is sec^2(3x+1)*3
What is the first derivative of tan(3x+1) ?
The first derivative of tan(3x+1) is sec^2(3x+1)*3