What is (\partial)/(\partial z)(xz+e^{-x^2+y}) ?

The answer to (\partial)/(\partial z)(xz+e^{-x^2+y}) is x

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(\partial)/(\partial z)(xz+e^{-x^2+y})

\frac{\partial}{\partial z} (x z + e^{- x^{2} + y})

x

Solution steps

\frac{\partial}{\partial z} (x z + e^{- x^{2} + y})

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x z) + \frac{\partial}{\partial z} (e^{- x^{2} + y})

\frac{\partial}{\partial z} (x z) = x

\frac{\partial}{\partial z} (e^{- x^{2} + y}) = 0

= x + 0

Simplify

= x

x \cdot (\frac{d y}{d x}) + y = 3

n = 1 \sum \infty 0. 5^{n}

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x^{4} - x^{3} - 4 x^{2} + 3 x + 5, 12 x^{2} - 6 x - 8

\int 8 x e^{- x} d x

What is (\partial)/(\partial z)(xz+e^{-x^2+y}) ?
The answer to (\partial)/(\partial z)(xz+e^{-x^2+y}) is x