What is the tangent of f(x)=5-5x^2,(-2,-15) ?

The tangent of f(x)=5-5x^2,(-2,-15) is y=20x+25

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tangent of f(x)=5-5x^2,(-2,-15)

tangent of

f (x) = 5 - 5 x^{2}, (- 2, - 15)

y = 20 x + 25

Solution steps

Find the slope of

f (x) = 5 - 5 x^{2} : \frac{df ( x )}{d x} = - 10 x

Compute the slope of

f (x) = 5 - 5 x^{2}

(- 2, - 15) : m = 20

Find the line with slope m=

20

and passing through

(- 2, - 15) : y = 20 x + 25

y = 20 x + 25

f (x) = 5^{1 - x}

\int \frac{x ^{2} + 1}{x ^{3} + x ^{2} - 2 x} d x

\int \frac{e ^{2 x}}{e ^{2 x}} d x

f (x) = \frac{( 4 x ^{5} + 8 )}{x ^{3}}

f (x) = 9 x^{\frac{1}{3}}

What is the tangent of f(x)=5-5x^2,(-2,-15) ?
The tangent of f(x)=5-5x^2,(-2,-15) is y=20x+25