What is (\partial}{\partial x}(\frac{(7x+7y))/z) ?

The answer to (\partial}{\partial x}(\frac{(7x+7y))/z) is 7/z

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(\partial}{\partial x}(\frac{(7x+7y))/z)

\frac{\partial}{\partial x} (\frac{( 7 x + 7 y )}{z})

\frac{7}{z}

Solution steps

\frac{\partial}{\partial x} (\frac{( 7 x + 7 y )}{z})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{z} \frac{\partial}{\partial x} (7 x + 7 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{z} (\frac{\partial}{\partial x} (7 x) + \frac{\partial}{\partial x} (7 y))

\frac{\partial}{\partial x} (7 x) = 7

\frac{\partial}{\partial x} (7 y) = 0

= \frac{1}{z} (7 + 0)

Simplify

\frac{1}{z} (7 + 0) : \frac{7}{z}

= \frac{7}{z}

x \to 2 lim (\frac{5}{x ^{4} - 16})

t \to 0 lim ((\frac{3}{t 1 + t}) - \frac{3}{t})

\int 2 + 4 y^{2} d y

\frac{d}{d x} (x 49 - x^{2})

\int x^{2} + 5 d x

What is (\partial}{\partial x}(\frac{(7x+7y))/z) ?
The answer to (\partial}{\partial x}(\frac{(7x+7y))/z) is 7/z