What is (\partial)/(\partial x)((3x^2)/(y-5)) ?

The answer to (\partial)/(\partial x)((3x^2)/(y-5)) is (6x)/(y-5)

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(\partial)/(\partial x)((3x^2)/(y-5))

\frac{\partial}{\partial x} (\frac{3 x ^{2}}{y - 5})

\frac{6 x}{y - 5}

Solution steps

\frac{\partial}{\partial x} (\frac{3 x ^{2}}{y - 5})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3}{y - 5} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{3}{y - 5} \cdot 2 x^{2 - 1}

Simplify

\frac{3}{y - 5} \cdot 2 x^{2 - 1} : \frac{6 x}{y - 5}

= \frac{6 x}{y - 5}

\frac{\partial}{\partial z} (\frac{x + y}{z})

ln (1 - e^{- x})

\frac{d}{d x} (4 x^{2} + 3 x - 7)

\int \frac{( x ^{3} )}{25 - x ^{2}} d x

n = 2 \sum \infty \frac{1}{n n}

What is (\partial)/(\partial x)((3x^2)/(y-5)) ?
The answer to (\partial)/(\partial x)((3x^2)/(y-5)) is (6x)/(y-5)