What is the first derivative of 3x+pi^2 ?

The first derivative of 3x+pi^2 is 3

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derivative of 3x+pi^2

derivative of

3 x + π^{2}

3

Solution steps

\frac{d}{d x} (3 x + π^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (π^{2})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (π^{2}) = 0

= 3 + 0

Simplify

= 3

y = 4 x, x = 5, y = \frac{4}{x}

\int (y + 1) x^{2} sin (\frac{x y}{2}) d y

\frac{d}{d x} (\frac{2}{x ^{3}})

x \to 0 lim (x^{2} ln (x))

1 - t^{2}