What is the derivative of-2x^2+36ln(x) ?

The derivative of-2x^2+36ln(x) is -4x+(36)/x

What is the first derivative of-2x^2+36ln(x) ?

The first derivative of-2x^2+36ln(x) is -4x+(36)/x

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\frac{d}{d x} (- 2 x^{2} + 36 ln (x))

- 4 x + \frac{36}{x}

Solution steps

\frac{d}{d x} (- 2 x^{2} + 36 ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (36 ln (x))

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (36 ln (x)) = \frac{36}{x}

= - 4 x + \frac{36}{x}

\int e^{s} d s

y^{^{'}} - 8 y^{2} cos (t) - 7 y^{2} sin (4 t) = 0

\int (\frac{e ^{x}}{1 + e ^{x}}) d x

\int 2 x (x^{2} + 14)^{9} d x

\frac{( d y )}{( d x )} = \frac{x}{y}

What is the derivative of-2x^2+36ln(x) ?
The derivative of-2x^2+36ln(x) is -4x+(36)/x
What is the first derivative of-2x^2+36ln(x) ?
The first derivative of-2x^2+36ln(x) is -4x+(36)/x