What is (\partial)/(\partial x)(-e^xcos(y)) ?

The answer to (\partial)/(\partial x)(-e^xcos(y)) is -cos(y)e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(-e^xcos(y))

\frac{\partial}{\partial x} (- e^{x} cos (y))

- cos (y) e^{x}

Solution steps

\frac{\partial}{\partial x} (- e^{x} cos (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - cos (y) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= - cos (y) e^{x}

\int csc^{2} (5 t) d t

y = \frac{3}{x}, y = 12 x, y = \frac{x}{3}

y^{^{'}} + 5 y = e^{(- 2 x)}

p (θ) = 3 θ

y = (x + 1)^{x}

What is (\partial)/(\partial x)(-e^xcos(y)) ?
The answer to (\partial)/(\partial x)(-e^xcos(y)) is -cos(y)e^x