What is the integral of (22)/((1-x^2)^{3/2)} ?

The integral of (22)/((1-x^2)^{3/2)} is (22x)/((1-x^2)^{1/2)}+C

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integral of (22)/((1-x^2)^{3/2)}

\int \frac{22}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

\frac{22 x}{( 1 - x ^{2} ) ^{\frac{1}{2}}} + C

Solution steps

\int \frac{22}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 22 \cdot \int \frac{1}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

Apply Trigonometric Substitution

: \int sec^{2} (u) d u

= 22 \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= 22 tan (u)

Substitute back

u = arcsin (x)

= 22 tan (arcsin (x))

Simplify

22 tan (arcsin (x)) : \frac{22 x}{( 1 - x ^{2} ) ^{\frac{1}{2}}}

= \frac{22 x}{( 1 - x ^{2} ) ^{\frac{1}{2}}}

Add a constant to the solution

= \frac{22 x}{( 1 - x ^{2} ) ^{\frac{1}{2}}} + C

\frac{\partial}{\partial x} (2 x arcsin (\frac{x}{y}))

y = x^{- 3}, 1 \leq x \leq 5

y = \frac{- 1}{3 sin ^{3} ( x )}

\int (3 t) d t

\int x + tan (x) d x

What is the integral of (22)/((1-x^2)^{3/2)} ?
The integral of (22)/((1-x^2)^{3/2)} is (22x)/((1-x^2)^{1/2)}+C