What is the integral of (-2)/(x^2) ?

The integral of (-2)/(x^2) is 2/x+C

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integral of (-2)/(x^2)

\int \frac{- 2}{x ^{2}} d x

\frac{2}{x} + C

Solution steps

\int \frac{- 2}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - 2 (- \frac{1}{x})

Simplify

- 2 (- \frac{1}{x}) : \frac{2}{x}

= \frac{2}{x}

Add a constant to the solution

= \frac{2}{x} + C

\frac{d y}{d x} = \frac{x}{y ^{3}}

\frac{d y}{d t} + \frac{t}{t ^{2} - 9} y = \frac{e ^{t}}{t - 6}

n = 0 \sum \infty - 4 (- \frac{1}{6})^{n}

\frac{d}{d x} (e^{\frac{x}{2}} cos (x))

\frac{d y}{d x} = 9 x^{2} y