What is the derivative of f(x)=4x^2cos(x)-9x ?

The derivative of f(x)=4x^2cos(x)-9x is 4(2xcos(x)-x^2sin(x))-9

What is the first derivative of f(x)=4x^2cos(x)-9x ?

The first derivative of f(x)=4x^2cos(x)-9x is 4(2xcos(x)-x^2sin(x))-9

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derivative of

f (x) = 4 x^{2} cos (x) - 9 x

4 (2 x cos (x) - x^{2} sin (x)) - 9

Solution steps

\frac{d}{d x} (4 x^{2} cos (x) - 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2} cos (x)) - \frac{d}{d x} (9 x)

\frac{d}{d x} (4 x^{2} cos (x)) = 4 (2 x cos (x) - x^{2} sin (x))

\frac{d}{d x} (9 x) = 9

= 4 (2 x cos (x) - x^{2} sin (x)) - 9

\frac{d}{d x} (700 x^{2} - 0.2 x)

\int \frac{5}{6} sec (x) tan (x) d x

y^{2} d x + 2 x y d y = 0

\frac{d}{d t} (\frac{t}{s})

What is the derivative of f(x)=4x^2cos(x)-9x ?
The derivative of f(x)=4x^2cos(x)-9x is 4(2xcos(x)-x^2sin(x))-9
What is the first derivative of f(x)=4x^2cos(x)-9x ?
The first derivative of f(x)=4x^2cos(x)-9x is 4(2xcos(x)-x^2sin(x))-9