What is the derivative of f(x)=(x^2-99)/(x-10) ?

The derivative of f(x)=(x^2-99)/(x-10) is (x^2-20x+99)/((x-10)^2)

What is the first derivative of f(x)=(x^2-99)/(x-10) ?

The first derivative of f(x)=(x^2-99)/(x-10) is (x^2-20x+99)/((x-10)^2)

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derivative of

f (x) = \frac{x ^{2} - 99}{x - 10}

\frac{x ^{2} - 20 x + 99}{( x - 10 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 99}{x - 10})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 99 ) ( x - 10 ) - \frac{d}{d x} ( x - 10 ) ( x ^{2} - 99 )}{( x - 10 ) ^{2}}

\frac{d}{d x} (x^{2} - 99) = 2 x

\frac{d}{d x} (x - 10) = 1

= \frac{2 x ( x - 10 ) - 1 \cdot ( x ^{2} - 99 )}{( x - 10 ) ^{2}}

Simplify

\frac{2 x ( x - 10 ) - 1 \cdot ( x ^{2} - 99 )}{( x - 10 ) ^{2}} : \frac{x ^{2} - 20 x + 99}{( x - 10 ) ^{2}}

= \frac{x ^{2} - 20 x + 99}{( x - 10 ) ^{2}}

f (x) = e^{5 x^{2}}

\frac{d y}{d x} = 2 y + x^{2} + 7

\int 16 x^{3} ln (x) d x

\int_{0}^{\frac{π}{4}} sin^{2} (x) d x

f (t) = \frac{1}{t}

What is the derivative of f(x)=(x^2-99)/(x-10) ?
The derivative of f(x)=(x^2-99)/(x-10) is (x^2-20x+99)/((x-10)^2)
What is the first derivative of f(x)=(x^2-99)/(x-10) ?
The first derivative of f(x)=(x^2-99)/(x-10) is (x^2-20x+99)/((x-10)^2)