What is the derivative of y=e^{3e^x} ?

The derivative of y=e^{3e^x} is 3e^{3e^x+x}

What is the first derivative of y=e^{3e^x} ?

The first derivative of y=e^{3e^x} is 3e^{3e^x+x}

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derivative of

y = e^{3 e^{x}}

3 e^{3 e^{x} + x}

Solution steps

\frac{d}{d x} (e^{3 e^{x}})

Apply the chain rule:

e^{3 e^{x}} \frac{d}{d x} (3 e^{x})

= e^{3 e^{x}} \frac{d}{d x} (3 e^{x})

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

= e^{3 e^{x}} \cdot 3 e^{x}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{3 e^{x}} e^{x} = e^{3 e^{x} + x}

= 3 e^{3 e^{x} + x}

f (x) = arctan (cos (x))

\frac{d}{d x} (4 x^{6} - 3 x^{5} - 10 x^{2} + 5 x + 16)

x \to 3 lim (6)

(1 + e^{x}) y y^{^{'}} = e^{x}

\frac{d}{d x} (36 e^{- 6 x})

What is the derivative of y=e^{3e^x} ?
The derivative of y=e^{3e^x} is 3e^{3e^x+x}
What is the first derivative of y=e^{3e^x} ?
The first derivative of y=e^{3e^x} is 3e^{3e^x+x}