What is area f(x)=x,g(x)=sqrt(x),x=0,x=2 ?

The answer to area f(x)=x,g(x)=sqrt(x),x=0,x=2 is (7-4sqrt(2))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area f(x)=x,g(x)=sqrt(x),x=0,x=2

area

f (x) = x, g (x) = x, x = 0, x = 2

\frac{7 - 4 2}{3}

Decimal Notation

0.44771 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x - x d x

Solve

\int_{0}^{2} x - x d x : \frac{7 - 4 2}{3}

The area is:

= \frac{7 - 4 2}{3}

y^{^{''}} + 2 y^{^{'}} + 5 y = 0, y (0) = 1, y^{^{'}} (0) = 2

n = 1 \sum \infty \frac{1}{n ^{3}}

\int 10 cos (100 x) d x

\frac{2}{x - 3}

\int \frac{1}{x ^{2} - 8 x + 65} d x

What is area f(x)=x,g(x)=sqrt(x),x=0,x=2 ?
The answer to area f(x)=x,g(x)=sqrt(x),x=0,x=2 is (7-4sqrt(2))/3