What is the derivative of 1/(sqrt(16+x^2)) ?

The derivative of 1/(sqrt(16+x^2)) is -x/((16+x^2)^{3/2)}

What is the first derivative of 1/(sqrt(16+x^2)) ?

The first derivative of 1/(sqrt(16+x^2)) is -x/((16+x^2)^{3/2)}

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derivative of

\frac{1}{16 + x ^{2}}

- \frac{x}{( 16 + x ^{2} ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{16 + x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((16 + x^{2})^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( 16 + x ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (16 + x^{2})

= - \frac{1}{2 ( 16 + x ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (16 + x^{2})

\frac{d}{d x} (16 + x^{2}) = 2 x

= - \frac{1}{2 ( 16 + x ^{2} ) ^{\frac{3}{2}}} \cdot 2 x

Simplify

- \frac{1}{2 ( 16 + x ^{2} ) ^{\frac{3}{2}}} \cdot 2 x : - \frac{x}{( 16 + x ^{2} ) ^{\frac{3}{2}}}

= - \frac{x}{( 16 + x ^{2} ) ^{\frac{3}{2}}}

n = 1 \sum \infty (\frac{4}{10})^{n}

\int \frac{2 x + 2}{x ^{2} - 4 x + 9} d x

\int - t e^{- s t} d t

\int_{- 1}^{2} ∣ e^{x} - 1 ∣ d x

\frac{2}{s + 1} + \frac{32 s}{s ^{2} + 9}

What is the derivative of 1/(sqrt(16+x^2)) ?
The derivative of 1/(sqrt(16+x^2)) is -x/((16+x^2)^{3/2)}
What is the first derivative of 1/(sqrt(16+x^2)) ?
The first derivative of 1/(sqrt(16+x^2)) is -x/((16+x^2)^{3/2)}