What is the d/(dθ)(2/(sin(θ))) ?

The d/(dθ)(2/(sin(θ))) is -2cot(θ)csc(θ)

What is the first d/(dθ)(2/(sin(θ))) ?

The first d/(dθ)(2/(sin(θ))) is -2cot(θ)csc(θ)

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\frac{d}{d θ} (\frac{2}{sin ( θ )})

- 2 cot (θ) csc (θ)

Solution steps

\frac{d}{d θ} (\frac{2}{sin ( θ )})

Simplify

\frac{2}{sin ( θ )} : 2 csc (θ)

= \frac{d}{d θ} (2 csc (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d θ} (csc (θ))

Apply the common derivative:

\frac{d}{d θ} (csc (θ)) = - cot (θ) csc (θ)

= 2 (- cot (θ) csc (θ))

Simplify

= - 2 cot (θ) csc (θ)

\frac{d y}{d x} = - \frac{y ^{2}}{1 + y ^{2}} e^{- x}, y (0) = 1

\int (x + 1) (x + 3)^{2} d x

\frac{d}{d x} (\frac{32}{x})

- x^{2} + 9, 1.25 x + 3

y^{^{'}} - y = 9 t e^{2 t}, y (0) = 1

What is the d/(dθ)(2/(sin(θ))) ?
The d/(dθ)(2/(sin(θ))) is -2cot(θ)csc(θ)
What is the first d/(dθ)(2/(sin(θ))) ?
The first d/(dθ)(2/(sin(θ))) is -2cot(θ)csc(θ)