What is inverse oflaplace 4/(s+4) ?

The answer to inverse oflaplace 4/(s+4) is 4e^{-4t}

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inverse oflaplace 4/(s+4)

inverse laplace

\frac{4}{s + 4}

4 e^{- 4 t}

Solution steps

L^{- 1} {\frac{4}{s + 4}}

= L^{- 1} {4 \cdot \frac{1}{s + 4}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {\frac{1}{s + 4}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 4}} = e^{- 4 t}

= 4 e^{- 4 t}

x \to 2 lim (3 x^{3} - 12 x - 4)

f (x) = x, g (x) = 2, h (x) = x

\int sin (6 x - 10) d x

f (x) = x^{2} + 2, (- 4, 18)

\frac{d}{d x} (sec^{2} (x) + csc^{2} (x))

What is inverse oflaplace 4/(s+4) ?
The answer to inverse oflaplace 4/(s+4) is 4e^{-4t}