What is the derivative of g(h,x(h(x))) ?

The derivative of g(h,x(h(x))) is h(derivative of {g}(h,x)x+1*{g}(h,x))

What is the first derivative of g(h,x(h(x))) ?

The first derivative of g(h,x(h(x))) is h(derivative of {g}(h,x)x+1*{g}(h,x))

Popular >

\frac{d}{d x} (g (h, x) (h (x)))

h (\frac{d}{d x} (g (h, x)) x + 1 \cdot g (h, x))

Solution steps

\frac{d}{d x} (g (h, x) (h (x)))

Treat

h

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= h \frac{d}{d x} (g (h, x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = g (h, x), g = x

= h (\frac{d}{d x} (g (h, x)) x + \frac{d x}{d x} g (h, x))

\frac{d x}{d x} = 1

= h (\frac{d}{d x} (g (h, x)) x + 1 \cdot g (h, x))

\int \frac{cos ( x )}{7 + sin ^{2} ( x )} d x

f (x) = (x + 2)^{\frac{2}{3}} (2 x^{2} - 5)^{3}

2 - ∣ x ∣, x^{2}

\frac{d y}{d x} + \frac{2 y}{x} = \frac{9}{x}

\frac{\partial}{\partial x} (x^{2} - x y + y^{2})

What is the derivative of g(h,x(h(x))) ?
The derivative of g(h,x(h(x))) is h(derivative of {g}(h,x)x+1*{g}(h,x))
What is the first derivative of g(h,x(h(x))) ?
The first derivative of g(h,x(h(x))) is h(derivative of {g}(h,x)x+1*{g}(h,x))