What is the tangent of y=5tan(x),\at x= pi/3 ?

The tangent of y=5tan(x),\at x= pi/3 is y=20x+5sqrt(3)-(20pi)/3

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tangent of y=5tan(x),\at x= pi/3

tangent of

y = 5 tan (x), at x = \frac{π}{3}

y = 20 x + 53 - \frac{20 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{3}, 53)

Find the slope of

y = 5 tan (x) : \frac{d y}{d x} = 5 sec^{2} (x)

Compute the slope of

y = 5 tan (x)

x = \frac{π}{3} : m = 20

Find the line with slope m=

20

and passing through

(\frac{π}{3}, 53) : y = 20 x + 53 - \frac{20 π}{3}

y = 20 x + 53 - \frac{20 π}{3}

\frac{d}{d x} (- \frac{1}{4 x})

ln (x - 1)

f (x) = ln (12 x)

\frac{d}{d x} (((x + 5)^{5} - 1)^{4})

\frac{\partial}{\partial x} (\frac{1}{1 - e ^{- x}})

What is the tangent of y=5tan(x),\at x= pi/3 ?
The tangent of y=5tan(x),\at x= pi/3 is y=20x+5sqrt(3)-(20pi)/3