What is the integral from-infinity to 0 of 1/(4-8x) ?

The integral from-infinity to 0 of 1/(4-8x) is diverges

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integral from-infinity to 0 of 1/(4-8x)

\int_{- \infty}^{0} \frac{1}{4 - 8 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{4 - 8 x} d x

Compute the indefinite integral:

\int \frac{1}{4 - 8 x} d x = - \frac{1}{8} ln ∣ 4 - 8 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{4 - 8 x} d x =

diverges

= diverges

y^{^{'}} = \frac{x}{( 1 + 2 y )}, y (- 1) = 0

\frac{d}{d x} (cos (x) - 2 sin (x))

x \to 5 - lim (\frac{2}{x - 5})

\frac{d}{d x} (x^{2} y^{3} + x e^{x y})

\int (10 x + 0.5) d x

What is the integral from-infinity to 0 of 1/(4-8x) ?
The integral from-infinity to 0 of 1/(4-8x) is diverges