What is the limit as x approaches 1 of 2/(x^2-7x+6) ?

The limit as x approaches 1 of 2/(x^2-7x+6) is diverges

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limit as x approaches 1 of 2/(x^2-7x+6)

x \to 1 lim (\frac{2}{x ^{2} - 7 x + 6})

diverges

Solution steps

x \to 1 lim (\frac{2}{x ^{2} - 7 x + 6})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{2}{x ^{2} - 7 x + 6}) = - \infty

x \to 1 - lim (\frac{2}{x ^{2} - 7 x + 6}) = \infty

= diverges

f (x) = x^{3} cos (x)

\int e^{- r^{2}} \cdot r d r

\int_{0}^{1} sin^{3} (\frac{π}{2} x) d x

x \to 0 lim (3 x^{2} + 1)

\int_{0}^{x} t (e^{2 t^{3}} - 1) d t

What is the limit as x approaches 1 of 2/(x^2-7x+6) ?
The limit as x approaches 1 of 2/(x^2-7x+6) is diverges