What is area 2x+5,x^2+2x+1,[-2,2] ?

The answer to area 2x+5,x^2+2x+1,[-2,2] is 32/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 2x+5,x^2+2x+1,[-2,2]

area

2 x + 5, x^{2} + 2 x + 1, [- 2, 2]

\frac{32}{3}

Decimal Notation

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} 2 x + 5 - (x^{2} + 2 x + 1) d x

Solve

\int_{- 2}^{2} 2 x + 5 - (x^{2} + 2 x + 1) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

\int 4 x^{\frac{1}{3}} + 2 x^{- \frac{2}{3}} + 9 d x

y = x^{2} - 6, y = 5 x

\frac{d}{d x} (sin (tan (sin (x))))

y = 1 - 4 x

\int x \cdot e^{- b (x - a)^{2}} d x

What is area 2x+5,x^2+2x+1,[-2,2] ?
The answer to area 2x+5,x^2+2x+1,[-2,2] is 32/3