What is the integral of tan(3)(x)sec(7)(x) ?

The integral of tan(3)(x)sec(7)(x) is 1/3 tan(3)sec(7)x^3+C

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integral of tan(3)(x)sec(7)(x)

\int tan (3) (x) sec (7) (x) d x

\frac{1}{3} tan (3) sec (7) x^{3} + C

Solution steps

\int tan (3) x sec (7) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= tan (3) sec (7) \cdot \int xx d x

Simplify

xx : x^{2}

= tan (3) sec (7) \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= tan (3) sec (7) \frac{x ^{3}}{3}

Simplify

tan (3) sec (7) \frac{x ^{3}}{3} : \frac{1}{3} tan (3) sec (7) x^{3}

= \frac{1}{3} tan (3) sec (7) x^{3}

Add a constant to the solution

= \frac{1}{3} tan (3) sec (7) x^{3} + C

\frac{d}{d x} (\frac{x}{1 + ( 1.5574 + 5.43 x ^{2} ) ^{2}})

\int x^{5} e^{- 3 x} d x

n = 1 \sum \infty \frac{n !}{10 2 ^{n}}

f (x) = - \frac{x ^{3} + x - 1}{2}

What is the integral of tan(3)(x)sec(7)(x) ?
The integral of tan(3)(x)sec(7)(x) is 1/3 tan(3)sec(7)x^3+C