What is the derivative of (2x^2-4^3) ?

The derivative of (2x^2-4^3) is 12x(2x^2-4)^2

What is the first derivative of (2x^2-4^3) ?

The first derivative of (2x^2-4^3) is 12x(2x^2-4)^2

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\frac{d}{d x} ((2 x^{2} - 4)^{3})

12 x (2 x^{2} - 4)^{2}

Solution steps

\frac{d}{d x} ((2 x^{2} - 4)^{3})

Apply the chain rule:

3 (2 x^{2} - 4)^{2} \frac{d}{d x} (2 x^{2} - 4)

= 3 (2 x^{2} - 4)^{2} \frac{d}{d x} (2 x^{2} - 4)

\frac{d}{d x} (2 x^{2} - 4) = 4 x

= 3 (2 x^{2} - 4)^{2} \cdot 4 x

Simplify

= 12 x (2 x^{2} - 4)^{2}

\int sin (3 x) sin (n x) d x

(1 - t) (3 + t^{2})^{- 1}

y = \frac{sin ( x )}{x}

\frac{x + 5}{x - 5}

y^{^{'}} = 5 x + y

What is the derivative of (2x^2-4^3) ?
The derivative of (2x^2-4^3) is 12x(2x^2-4)^2
What is the first derivative of (2x^2-4^3) ?
The first derivative of (2x^2-4^3) is 12x(2x^2-4)^2