What is the integral of xsqrt(9x^2+4) ?

The integral of xsqrt(9x^2+4) is 1/27 (9x^2+4)^{3/2}+C

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integral of xsqrt(9x^2+4)

\int x 9 x^{2} + 4 d x

\frac{1}{27} (9 x^{2} + 4)^{\frac{3}{2}} + C

Solution steps

\int x 9 x^{2} + 4 d x

Apply u-substitution

: \int \frac{u}{18} d u

= \int \frac{u}{18} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{18} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{18} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 9 x^{2} + 4

= \frac{1}{18} \cdot \frac{2}{3} (9 x^{2} + 4)^{\frac{3}{2}}

Simplify

\frac{1}{18} \cdot \frac{2}{3} (9 x^{2} + 4)^{\frac{3}{2}} : \frac{1}{27} (9 x^{2} + 4)^{\frac{3}{2}}

= \frac{1}{27} (9 x^{2} + 4)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{27} (9 x^{2} + 4)^{\frac{3}{2}} + C

\int x^{2} e^{17 x} d x

\frac{1}{s - 5} e^{- s}

a x^{2} + ∣ x ∣^{3}

y^{^{'}} = \frac{- 1 + x + y}{1 + x}

\frac{9 - ln ( x )}{ln ( x ) - 1}

What is the integral of xsqrt(9x^2+4) ?
The integral of xsqrt(9x^2+4) is 1/27 (9x^2+4)^{3/2}+C