What is the derivative of 900x-0.1x^2 ?

The derivative of 900x-0.1x^2 is 900-0.2x

What is the first derivative of 900x-0.1x^2 ?

The first derivative of 900x-0.1x^2 is 900-0.2x

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derivative of

900 x - 0.1 x^{2}

900 - 0.2 x

Solution steps

\frac{d}{d x} (900 x - 0.1 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (900 x) - \frac{d}{d x} (0.1 x^{2})

\frac{d}{d x} (900 x) = 900

\frac{d}{d x} (0.1 x^{2}) = 0.2 x

= 900 - 0.2 x

\int \frac{cos ( 3 x )}{sin ^{4} ( 3 x )} d x

f (x) = 2 x^{2} - 18 x + 5, at x = 0

x \to \infty lim (\frac{3 x ^{2} - x - 2}{5 x ^{2} - 4 x + 1})

f (x) = \frac{x ^{2}}{3 + 8 x}

(\frac{x ^{2}}{2})^{^{'}}

What is the derivative of 900x-0.1x^2 ?
The derivative of 900x-0.1x^2 is 900-0.2x
What is the first derivative of 900x-0.1x^2 ?
The first derivative of 900x-0.1x^2 is 900-0.2x