What is the integral from-35 to 0 of 1/(sqrt(1-x)) ?

The integral from-35 to 0 of 1/(sqrt(1-x)) is 10

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integral from-35 to 0 of 1/(sqrt(1-x))

\int_{- 35}^{0} \frac{1}{1 - x} d x

10

Solution steps

\int_{- 35}^{0} \frac{1}{1 - x} d x

Apply u-substitution

: \int_{36}^{1} - \frac{1}{u} d u

= \int_{36}^{1} - \frac{1}{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{36} - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{1}^{36} \frac{1}{u} d u)

Apply the Power Rule

: [2 u^{\frac{1}{2}}]_{1}^{36}

= - (- [2 u^{\frac{1}{2}}]_{1}^{36})

Simplify

- (- [2 u^{\frac{1}{2}}]_{1}^{36}) : [2 u]_{1}^{36}

= [2 u]_{1}^{36}

Compute the boundaries:

10

= 10

\int 2 x^{2} e^{x^{2}} d x

\int \frac{14}{x} d x

f (x) = x^{2} \cdot (x^{3} + 2)

\frac{d y}{d x} = \frac{16 x}{e ^{y}}

y^{^{''}} + 4 y = 12 sin (2 x)

What is the integral from-35 to 0 of 1/(sqrt(1-x)) ?
The integral from-35 to 0 of 1/(sqrt(1-x)) is 10