What is the derivative of (2x^3+9x^5) ?

The derivative of (2x^3+9x^5) is 5(2x^3+9x)^4(6x^2+9)

What is the first derivative of (2x^3+9x^5) ?

The first derivative of (2x^3+9x^5) is 5(2x^3+9x)^4(6x^2+9)

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\frac{d}{d x} ((2 x^{3} + 9 x)^{5})

5 (2 x^{3} + 9 x)^{4} (6 x^{2} + 9)

Solution steps

\frac{d}{d x} ((2 x^{3} + 9 x)^{5})

Apply the chain rule:

5 (2 x^{3} + 9 x)^{4} \frac{d}{d x} (2 x^{3} + 9 x)

= 5 (2 x^{3} + 9 x)^{4} \frac{d}{d x} (2 x^{3} + 9 x)

\frac{d}{d x} (2 x^{3} + 9 x) = 6 x^{2} + 9

= 5 (2 x^{3} + 9 x)^{4} (6 x^{2} + 9)

\int 12 x^{2} - 5 x + 4 d x

\int_{- 2}^{2} \frac{1}{x ^{2} + 4} d x

\frac{d}{d x} (e^{2 x + 5} + \frac{1}{e ^{x^{2}}})

\frac{\partial}{\partial x} (7 x cos (5 x y))

x y y^{^{'}} = 4 x^{2} + 2 y^{2}

What is the derivative of (2x^3+9x^5) ?
The derivative of (2x^3+9x^5) is 5(2x^3+9x)^4(6x^2+9)
What is the first derivative of (2x^3+9x^5) ?
The first derivative of (2x^3+9x^5) is 5(2x^3+9x)^4(6x^2+9)