What is (\partial)/(\partial x)(4y-2xy) ?

The answer to (\partial)/(\partial x)(4y-2xy) is -2y

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(\partial)/(\partial x)(4y-2xy)

\frac{\partial}{\partial x} (4 y - 2 x y)

- 2 y

Solution steps

\frac{\partial}{\partial x} (4 y - 2 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 y) - \frac{\partial}{\partial x} (2 x y)

\frac{\partial}{\partial x} (4 y) = 0

\frac{\partial}{\partial x} (2 x y) = 2 y

= 0 - 2 y

Simplify

= - 2 y

sin (2 x)

x \to 2 lim (\frac{1}{( x - 2 )})

\int \frac{2 x ^{3} + x ^{2} - 7 x + 7}{x ^{2} + x - 2} d x

\frac{\partial}{\partial y} (x y e^{4 y})

\int_{1}^{4} 1 + \frac{9}{4} x d x

What is (\partial)/(\partial x)(4y-2xy) ?
The answer to (\partial)/(\partial x)(4y-2xy) is -2y