What is the first derivative of 3x^2-3 ?

The first derivative of 3x^2-3 is 6x

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derivative of 3x^2-3

derivative of

3 x^{2} - 3

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3) = 0

= 6 x - 0

Simplify

= 6 x

x^{5} sin (x)

x \to 0 lim (\frac{1 - cos ^{2} ( 3 x )}{x ^{2}})

f (x) = 3 arcsin (x^{4})

\int_{0}^{1} 3 x^{2} d x

x \to - 2 lim (\frac{4 - x ^{2}}{x + 2})