What is the integral from 0 to 8 of 1/(\sqrt[3]{x)} ?

The integral from 0 to 8 of 1/(\sqrt[3]{x)} is 6

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integral from 0 to 8 of 1/(\sqrt[3]{x)}

6

Solution steps

Apply the Power Rule

: [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{8}

= [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{8}

Compute the boundaries:

6

= 6

\frac{\partial}{\partial x} (e^{x^{2}} + 2 y^{3})

\int (x + 1) ln (x) d x

f (x) = x^{2} x^{3} + 1

\int x \cdot f (x) d x

\frac{d}{d x} (2 y^{2} + 3 x)

What is the integral from 0 to 8 of 1/(\sqrt[3]{x)} ?
The integral from 0 to 8 of 1/(\sqrt[3]{x)} is 6