What is (\partial)/(\partial x)(cos(7x+4y+z)) ?

The answer to (\partial)/(\partial x)(cos(7x+4y+z)) is -sin(7x+4y+z)*7

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(\partial)/(\partial x)(cos(7x+4y+z))

\frac{\partial}{\partial x} (cos (7 x + 4 y + z))

- sin (7 x + 4 y + z) \cdot 7

Solution steps

\frac{\partial}{\partial x} (cos (7 x + 4 y + z))

Treat

y, z

as constants

Apply the chain rule:

- sin (7 x + 4 y + z) \frac{\partial}{\partial x} (7 x + 4 y + z)

= - sin (7 x + 4 y + z) \frac{\partial}{\partial x} (7 x + 4 y + z)

\frac{\partial}{\partial x} (7 x + 4 y + z) = 7

= - sin (7 x + 4 y + z) \cdot 7

x \to 0 lim (\frac{ln ( 1 - 3 x )}{x})

\int 15 x^{2} - cos (x) + C x + C d x

f (x) = \frac{( x ^{2} - 4 x )}{x + 1}

x \to 0 + lim (ln (\frac{7}{x ^{5}}))

15 y^{^{''}} + 7 y^{^{'}} - 2 y = 0

What is (\partial)/(\partial x)(cos(7x+4y+z)) ?
The answer to (\partial)/(\partial x)(cos(7x+4y+z)) is -sin(7x+4y+z)*7