What is (\partial)/(\partial x)((2*x)/(x^2-y^2)) ?

The answer to (\partial)/(\partial x)((2*x)/(x^2-y^2)) is (2(-x^2-y^2))/((x^2-y^2)^2)

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(\partial)/(\partial x)((2*x)/(x^2-y^2))

\frac{\partial}{\partial x} (\frac{2 \cdot x}{x ^{2} - y ^{2}})

\frac{2 ( - x ^{2} - y ^{2} )}{( x ^{2} - y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{2 x}{x ^{2} - y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (\frac{x}{x ^{2} - y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{\partial}{\partial x} ( x ) ( x ^{2} - y ^{2} ) - \frac{\partial}{\partial x} ( x ^{2} - y ^{2} ) x}{( x ^{2} - y ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x^{2} - y^{2}) = 2 x

= 2 \cdot \frac{1 \cdot ( x ^{2} - y ^{2} ) - 2 xx}{( x ^{2} - y ^{2} ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot ( x ^{2} - y ^{2} ) - 2 xx}{( x ^{2} - y ^{2} ) ^{2}} : \frac{2 ( - x ^{2} - y ^{2} )}{( x ^{2} - y ^{2} ) ^{2}}

= \frac{2 ( - x ^{2} - y ^{2} )}{( x ^{2} - y ^{2} ) ^{2}}

\frac{d}{d z} (\frac{y}{z})

\frac{d}{d x} ((\frac{x + 1}{x - 1})^{3})

\int y 4 + 4 y - 4 y^{2} d y

\frac{\partial}{\partial x} (y^{8} + 4 x^{3} y^{3})

[x^{2} (x^{2} + 6 x)]^{6}

What is (\partial)/(\partial x)((2*x)/(x^2-y^2)) ?
The answer to (\partial)/(\partial x)((2*x)/(x^2-y^2)) is (2(-x^2-y^2))/((x^2-y^2)^2)