What is the integral of (13)/(x^2+1) ?

The integral of (13)/(x^2+1) is 13arctan(x)+C

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integral of (13)/(x^2+1)

\int \frac{13}{x ^{2} + 1} d x

13 arctan (x) + C

Solution steps

\int \frac{13}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 13 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= 13 arctan (x)

Add a constant to the solution

= 13 arctan (x) + C

\frac{d y}{d x} = 3 y e^{x + 8}

x \to \infty lim ((- 1)^{x} \cdot (1 - \frac{1}{x ^{2}}))

\int sin^{2} (φ) d φ

f (x) = 4 x^{(2)} (x - 3)

x \to \infty lim (x^{2} + 2 x)

What is the integral of (13)/(x^2+1) ?
The integral of (13)/(x^2+1) is 13arctan(x)+C