What is the limit as x approaches 0 of ((8^x-1))/x ?

The limit as x approaches 0 of ((8^x-1))/x is 3ln(2)

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limit as x approaches 0 of ((8^x-1))/x

x \to 0 lim (\frac{( 8 ^{x} - 1 )}{x})

3 ln (2)

Decimal Notation

2.07944 \dots

Solution steps

x \to 0 lim (\frac{8 ^{x} - 1}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{3 ln ( 2 ) \cdot 8 ^{x}}{1})

= x \to 0 lim (\frac{3 ln ( 2 ) \cdot 8 ^{x}}{1})

Plug in the value

x = 0

= \frac{3 ln ( 2 ) \cdot 8 ^{0}}{1}

Simplify

= 3 ln (2)

\int \frac{d}{1} (x) d x

\int_{- 3}^{6} 3 + x d x

\frac{\partial}{\partial x} (e^{9 z})

x \to 0 lim (1 + x^{2})

\int (e^{y}) d y

What is the limit as x approaches 0 of ((8^x-1))/x ?
The limit as x approaches 0 of ((8^x-1))/x is 3ln(2)