What is inverse oflaplace 1/(s-5) ?

The answer to inverse oflaplace 1/(s-5) is e^{5t}

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inverse oflaplace 1/(s-5)

inverse laplace

\frac{1}{s - 5}

e^{5 t}

Solution steps

L^{- 1} {\frac{1}{s - 5}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 5}} = e^{5 t}

= e^{5 t}

y^{^{'}} + 6 y = 60, y (1) = 110

y^{^{'}} = 19 x y

\frac{s ^{2}}{s ^{3} + 2 \cdot s ^{2} - 1}

\int_{0}^{7} \frac{6 t}{( t - 8 ) ^{2}} d t

\frac{d}{d x} ((x^{2} + 1)^{x + 1})

What is inverse oflaplace 1/(s-5) ?
The answer to inverse oflaplace 1/(s-5) is e^{5t}