What is the derivative of 3/(sqrt(x+8)) ?

The derivative of 3/(sqrt(x+8)) is -3/(2(x+8)^{3/2)}

What is the first derivative of 3/(sqrt(x+8)) ?

The first derivative of 3/(sqrt(x+8)) is -3/(2(x+8)^{3/2)}

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\frac{d}{d x} (\frac{3}{x + 8})

- \frac{3}{2 ( x + 8 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{3}{x + 8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x + 8})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x + 8)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x + 8 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 8)

= - \frac{1}{2 ( x + 8 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 8)

\frac{d}{d x} (x + 8) = 1

= 3 (- \frac{1}{2 ( x + 8 ) ^{\frac{3}{2}}} \cdot 1)

Simplify

3 (- \frac{1}{2 ( x + 8 ) ^{\frac{3}{2}}} \cdot 1) : - \frac{3}{2 ( x + 8 ) ^{\frac{3}{2}}}

= - \frac{3}{2 ( x + 8 ) ^{\frac{3}{2}}}

\frac{3 x}{( x - 1 ) ^{4}}

\frac{d}{d x} (arctan (x^{2} + y^{2}))

\frac{d}{d y} (y - 1)

\int (\frac{1}{cos ( x )}) d x

6 - 5 x^{2}

What is the derivative of 3/(sqrt(x+8)) ?
The derivative of 3/(sqrt(x+8)) is -3/(2(x+8)^{3/2)}
What is the first derivative of 3/(sqrt(x+8)) ?
The first derivative of 3/(sqrt(x+8)) is -3/(2(x+8)^{3/2)}