What is the limit as x approaches 0 of (sqrt(1+x))/x ?

The limit as x approaches 0 of (sqrt(1+x))/x is diverges

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limit as x approaches 0 of (sqrt(1+x))/x

x \to 0 lim (\frac{1 + x}{x})

diverges

Solution steps

x \to 0 lim (\frac{1 + x}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1 + x}{x}) = \infty

x \to 0 - lim (\frac{1 + x}{x}) = - \infty

= diverges

y^{^{''}} = e^{- x}

\int cos (x t) d t

\int \frac{1}{8} d x

\int_{2}^{\infty} e^{- 4 x} d x

What is the limit as x approaches 0 of (sqrt(1+x))/x ?
The limit as x approaches 0 of (sqrt(1+x))/x is diverges