What is the integral of ((ln(x))^{34})/x ?

The integral of ((ln(x))^{34})/x is (ln^{35}(x))/(35)+C

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integral of ((ln(x))^{34})/x

\int \frac{( ln ( x ) ) ^{34}}{x} d x

\frac{ln ^{35} ( x )}{35} + C

Solution steps

\int \frac{( ln ( x ) ) ^{34}}{x} d x

Apply u-substitution

: \int u^{34} d u

= \int u^{34} d u

Apply the Power Rule

: \frac{u ^{35}}{35}

= \frac{u ^{35}}{35}

Substitute back

u = ln (x)

= \frac{ln ^{35} ( x )}{35}

Add a constant to the solution

= \frac{ln ^{35} ( x )}{35} + C

n = 1 \sum \infty \frac{n}{n ^{2} + 5}

\frac{d y}{d x} = \frac{y + 2}{x - 1}

\frac{d}{d x} (e^{x l n (a)})

y = 3 x (6 x - 5 x^{2})

y^{^{''}} - y^{^{'}} - 12 y = 0

What is the integral of ((ln(x))^{34})/x ?
The integral of ((ln(x))^{34})/x is (ln^{35}(x))/(35)+C