What is the integral from 1 to 2 of 1/t ?

The integral from 1 to 2 of 1/t is ln(2)

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integral from 1 to 2 of 1/t

\int_{1}^{2} \frac{1}{t} d t

ln (2)

Decimal Notation

0.69314 \dots

Solution steps

\int_{1}^{2} \frac{1}{t} d t

Use the common integral:

\int \frac{1}{t} d t = ln (∣ t ∣)

= [ln ∣ t ∣]_{1}^{2}

Compute the boundaries:

ln (2)

= ln (2)

\int (x^{2} - 3 x + 3) d x

\int e^{x} + sin (y) d x

x \to 0 lim ((1 + b x)^{\frac{1}{x}})

\int t^{2} + \frac{2 t - 1}{t ^{2} - 2 t + 1} d t

x \to - 1 lim (\frac{1}{1 + x ^{2}})

What is the integral from 1 to 2 of 1/t ?
The integral from 1 to 2 of 1/t is ln(2)