What is the derivative of sin(3x)+cos(8x) ?

The derivative of sin(3x)+cos(8x) is cos(3x)*3-sin(8x)*8

What is the first derivative of sin(3x)+cos(8x) ?

The first derivative of sin(3x)+cos(8x) is cos(3x)*3-sin(8x)*8

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derivative of

sin (3 x) + cos (8 x)

cos (3 x) \cdot 3 - sin (8 x) \cdot 8

Solution steps

\frac{d}{d x} (sin (3 x) + cos (8 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (3 x)) + \frac{d}{d x} (cos (8 x))

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

\frac{d}{d x} (cos (8 x)) = - sin (8 x) \cdot 8

= cos (3 x) \cdot 3 - sin (8 x) \cdot 8

(1 + x^{2}) (\frac{d y}{d x}) - 2 x y = 0

\int_{\frac{π}{2}}^{π} x - sin (x) d x

\frac{d y}{d x} = \frac{3 x}{4 y}

sec (3 sin (2 x))

x \to 0 lim (e^{x} - 1)

What is the derivative of sin(3x)+cos(8x) ?
The derivative of sin(3x)+cos(8x) is cos(3x)*3-sin(8x)*8
What is the first derivative of sin(3x)+cos(8x) ?
The first derivative of sin(3x)+cos(8x) is cos(3x)*3-sin(8x)*8