What is the integral of 1/(cos^2(s)) ?

The integral of 1/(cos^2(s)) is tan(s)+C

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integral of 1/(cos^2(s))

\int \frac{1}{cos ^{2} ( s )} d s

tan (s) + C

Solution steps

\int \frac{1}{cos ^{2} ( s )} d s

Use the common integral:

\int \frac{1}{cos ^{2} ( s )} d s = tan (s)

= tan (s)

Add a constant to the solution

= tan (s) + C

\frac{d}{d x} (\frac{16 x}{( x ^{2} + 4 ) ^{2}})

\frac{\partial}{\partial x} (3 arctan (\frac{y}{x}))

\int \frac{sec ( x ) tan ( x )}{sec ( x ) - 5} d x

\frac{d}{d y} (\frac{x}{y})

x^{2} - 7 x - 24, - x^{2} + 3 x + 4