What is the solution for t^2*(dx)/(dt)= 1/x ?

The solution for t^2*(dx)/(dt)= 1/x is x=sqrt(-2/t+c_{1)},x=-sqrt(-2/t+c_{1)}

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t^2*(dx)/(dt)= 1/x

t^{2} \cdot \frac{d x}{d t} = \frac{1}{x}

x = - \frac{2}{t} + c_{1}, x = - - \frac{2}{t} + c_{1}

Solution steps

t^{2} \cdot \frac{d x}{d t} = \frac{1}{x}

Solve separable ODE:

x = - \frac{2}{t} + c_{1}, x = - - \frac{2}{t} + c_{1}

x = - \frac{2}{t} + c_{1}, x = - - \frac{2}{t} + c_{1}

\frac{d}{d x} (8 x e^{4 x})

\int \frac{sin ^{2} ( x )}{x ^{2}} d x

f (x) = \frac{e ^{x}}{1 - e ^{x}}

15 y^{^{''}} - 7 y^{^{'}} - 4 y = 0

t \to 0 lim (tan (4 t))

What is the solution for t^2*(dx)/(dt)= 1/x ?
The solution for t^2*(dx)/(dt)= 1/x is x=sqrt(-2/t+c_{1)},x=-sqrt(-2/t+c_{1)}